Print Lines Between Two Patterns with SED

Question

I have a file with the content shown below:

***************Encrypted String***************
 ezF7LcHO0Zlb+8kkBeIwtA== 
**********************************************

I need to get only encrypted password from above. I used Google to search for an answer, and I got this example (below), but it didn't work:

sed -n '/***************Encrypted String***************/,/************************************‌**********/p' $file

I tried but it didn't work

what have you tried? see http://stackoverflow.com/questions/38972736/how-to-select-lines-between-two-patterns/38978201#38978201 for an example to solve this kind of problem — Sundeep, Sep 12 '16 at 12:47
actually i need to get only encrypted password from below. While i am google it i got above example but it didn't work *************Encrypted String************* ezF7LcHO0Zlb+8kkBeIwtA== — Sureshchandra Jarugula, Sep 12 '16 at 12:59
i need to get only encrypted password from below. While i am google it i got above example but it didn't work *************Encrypted String************* ezF7LcHO0Zlb+8kkBeIwtA==

sed -n '/*************Encrypted String***********/,/********************************************/p' $file is this works, i tryed but it didn't work — Sureshchandra Jarugula, Sep 12 '16 at 13:06
Please put your updates into the question. Leaving them in the comments makes it confusing and ambiguous for people trying to understand which is the most recent edit. — Chris Davies, Sep 12 '16 at 15:15

score 1 · Answer 1 · answered Sep 12 '16 at 15:28

The problem here is probably that * is a Regular Expression operator, so you have to escape it \* for it to be treated as a literal. Your examples and suggestions referencing the literals BEGIN and END would all have failed without this adaptation.

***************Encrypted String***************
 ezF7LcHO0Zlb+8kkBeIwtA== 
**********************************************

To extract the second line you could use either of these:

sed -n '0,/\*Encrypted String\*/d;p;q' "$file"
sed -n 2p "$file"

The first matches on *Encrypted String* and then prints the next line. Notice that the * characters are written as \* to ensure they are treated as literal asterisks. The second just prints line two of the file.

Print Lines Between Two Patterns with SED

1 Answers1